Math 114Q, Section 10
Second Exam
November 6, 2007
Answers

General guidelines

  1. (20 points) At Hanukkah (coming up in December) Jewish children play a game for pennies with the four sided spinning top shown here. When it's your turn you spin the top. This is what happens:
      letter showing  result
         gimmel       take all the pennies in the pot
         hey          take half the pennies in the pot
         shin         put one penny in the pot
         nun          nothing (next player's turn)
    

    1. What is the probability that a gimmel appears?

      Answer.

      The probability of a gimmel is 1/4 since each of the four sides of the dreidel is equally likely to shwo.

    2. What is the probability that the person spinning the dreidel wins something on her turn?

      Answer.

      Half the outcomes (gimmel and hey) are wins for the spinner, so the probability is 1/2.

    3. What is the probability that the person spinning the dreidel loses a penny twice in a row?

      Answer.

      The probability of losing twice in a row is (1/4)*(1/4) = 1/16.

    4. Suppose there are ten pennies in the pot when you spin. What would be the "fair price" to play? That is, on the average, how much would you expect to win?

      Answer.

      If you spin 100 times then on average there will be

        25 gimmels       worth       25*10   = 250 pennies
        25 heys          worth       25*5    = 125 pennies
        25 shins         worth       25*(-1) = -25 pennies
        25 nuns          worth       10*0    =   0 pennies
      
      so in 100 spins you collect (on average) 250+125-25 = 350 pennies. Therefore a fair price to pay for each spin is 350/100 = 3.5 pennies. If you did that you'd just break even (in the long run). That means each turn you collect (on average)

    5. (Extra credit) Why do you think the picture caption describes the four sides of the dreidel from right to left?

      Answer.

      Hebrew is written from right to left.

    The picture is from the web site www.myjewishlearning.com/holidays/Hanukkah/TO_Hanukkah_Home/Dreidel/Dreidel_Rules_357.htm#, where you can read more if you like. But you won't find anything else there to help with this question.

  2. (20 points) The flyer promoting CAJT.PK stock we discussed in class last Thursday says, in the small print disclaimer
    WHL has received 10 million shares of CAJT stock ... WHL has paid an advertising cost of nine hundred ninety thousand dollars to produce and distribute this public awareness mailer.

    1. Suppose CAJT stock is selling at $0.41/share. How much profit will WHL make if they sell their shares now?

      Answer.

      They will collect

                                   $ 
        10 million shares * 0.41 ----- = $4.1 million 
                                 share
      
      so their profit is
          $4.1 million - 0.99 million ~ $3.1 million .
      

    2. What is likely to happen to the stock price when WHL sells its 10 million shares and walks away with the profits?

      Answer.

      The stock price will fall rapidly when lots of shares are sold at one time.

    3. Estimate how many copies of the flyer WHL sent out. (Hint: you know how much they say they spent on production and distribution.)

      Answer.

      It costs 41 cents now to mail a letter. Presorted bulk mail is cheaper, so I'll estimate postage at 25 cents per flyer. For two sided color printing on heavy paper I'll estimate 50 cents per flyer. WHL spent about a million dollars ($990 thousand) so they sent out

                       1 flyer
         $1 million * --------- = 1.3 million flyers
                       $0.75
      

    4. (Extra Credit) WHL believes that the price of CAJT stock will rise significantly if at least 5,000 people buy some when they get the mailer. Use your answer to the previous problem to determine what percentage of the people receiving the mailing must respond in order for this to happen.

      Answer.

             5000 flyer responses
             -------------------- = 0.00384615385 ~ 0.4%
              1.3 million flyers
      
      A response rate of four tenths of one percent (four per thousand) would suit WHL just fine.

    5. (Extra Credit) WHL hopes their mailer will succeed in encouraging people to buy CAJT, so the price will go up. How much extra profit will they make for each penny increase in the stock price?

      Answer.

      Each extra penny is worth 10 million pennies (one per share), so an extra $100,000 in profit.

  3. (40 points) The following table shows the age distribution of the U.S. population in 2000, and the predicted age distribution for the year 2050. Values are in millions of people.
                        year   
        age range    2000   2050
           0-9      39.70   55.60
         10-19      40.86   53.56
         20-29      39.90   52.89
         30-39      43.24   52.85
         40-49      42.77   49.98
         50-59      31.35   46.26
         60-69      20.40   42.83
         70-79      16.28   32.57
         80+         9.25   33.70
    
    You can download that table directly into Excel from the link USPopulationProjection.xls.

    Answer the following questions. (Excel will help, of course!) Write the answers in your blue book (except for the chart).

    Turn in a printout of your entire spreadsheet (not just the chart) and also send the spreadsheet as an email attachment to yourself and to eb@cs.umb.edu. Make sure the data are not hidden by the chart.

    Answer.

    USPopulationProjectionAnswer.xls.

    1. What was the total population of the United States in 2000? What is the projected value for 2050?

      Answer.

      Excel summed the columns for me and told me the total in 2006 was 283.74 million and the projected total for 2050 was 420.22 million.

    2. Verify the result of your year 2000 calculation by finding the same number on a reliable web site. Do the numbers match exactly?

      Answer.

      From www.u-s-history.com/pages/h980.html:

      The official count of the U.S. population was 281421906 on April 1, 2000
      
      That's close enough to the 283.74 million in the data presented on the exam.

    3. What are the absolute and percentage increases in the U.S. population between 2000 and the projected value for 2050?

      Answer.

      Again Excel did the work. The absolute change was 136.48 million, an increase of 48.10%.

    4. Which age range shows the smallest percentage increase between 2000 and 2050? What are the absolute and percentage increases in that age range?

      Answer.

      The smallest percentage increase is 16.87% in the 40-49 age group. The absolute change for that group is 7.21 million people.

    5. Which age range shows the largest percentage increase between 2000 and 2050? What are the absolute and percentage increases in that age range?

      Answer.

      The greatest percentage increase is 264.21% in the 80+ age group! The absolute change for that group is 24.45 million people.

    6. Construct and properly label a column chart displaying the information in the table.

      Answer.

      See the spreadsheet. Since my name and the data source are on the spreadsheet and the instructions say to submit the whole spreadsheet I chose not to take the time to put them on the chart.

      I did arrange the chart so that it and the data would all print on one page.

    7. (Extra credit) Estimate the mean and median ages for each of the years 2000 and 2050. Describe how you did the work.

      Answer.

      To find the median age I computed (in Excel) the fraction of the population younger than each age, and looked for where 0.5 came. That told me the median age was about 30 in 2006 and would be about 35 in 2050.

      To find the mean age I assumed that each person in each cohort was at the middle of the age range for that cohort. Then I computed the total number of years those people had lived, by multiplying. Then I added up all the years and divided by the total number of people. That told me the mean ages in 2000 and 2050 are 36.3 and 40.8 respectively.

      I was surprised that the mean and median for 2050 were not even larger, given how dramatically the population will have aged.

  4. (20 points) Today's Boston Globe reports Newspaper circulation still on decline. Their web site provides these figures:
       Newspaper			circulation	change
       ---------                    -----------     ------   
      USA Today			2,293,137	up 1.04%
      The Wall Street Journal	2,011,882	down 1.53%
      The New York Times		1,037,828	down 4.51%
      Los Angeles Times		779,682		up 0.50%
      New York Daily News		681,415		down 1.73%
      New York Post  		667,119		down 5.24%
      The Washington Post		635,087		down 3.23%
      Chicago Tribune		559,404		down 2.90%
      Houston Chronicle		507,437		down 0.13%
      Newsday, Long Island		387,503		down 5.62%
      The Arizona Republic		382,414		down 3.75%
      The Dallas Morning News	373,586		down 7.68%
      San Francisco Chronicle	365,234		down 2.29%
      The Boston Globe		360,695		down 6.66%
      The Star-Ledger (Newark, NJ)	353,003		down 2.78%
      The Philadelphia Inquirer	338,260		up 2.31%
      Star Tribune (Minneapolis)	335,443		down 6.53%
      The Plain Dealer (Cleveland)	334,195		down 0.81%
      Detroit Free Press		320,125		down 2.61%
      Atlanta Journal-Constitution	318,350		down 9.08%
    

    We've downloaded them to Excel and put them in spreadsheet NewspaperCirculation.xls.

    Answer.

    For the answers, see NewspaperCirculationAnswer.xls.

    1. What was the mean circulation for these newspapers?

      Answer.

      The mean daily circulation is 652089.95 or about 6.5 million. (I used the Excel AVERAGE function.)

    2. What was the median circulation for these newspapers?

      Answer.

      The median daily circulation is 384958.5 or about 3.8 million. (I used the Excel MEDIAN function.)

    3. Why are the mean and the median so different?

      Answer.

      The median is much less than the mean because there are a few papers with a very high daily circulation. This is exactly what we saw happen with the Wing Aero salary structure in class.

    4. If asked to report the mode for these circulation figures, what would you say?

    Answer.

    I'd say the mode was somewhere in the mid 300 thousands. That would clearly be the most common value if we grouped the circulation figures into ranges 100K-200K, 200K-300K, 300K-400K and so on.

    Heres the link to the complete article: www.boston.com/business/globe/articles/2007/11/06/newspaper_circulation_still_on_decline/. There's nothing there that will help you with the questions on this exam.